A container was found in the home of the victim that contained 103 g of ethylene glycol in 340 g of liquid. What was the percentage of ethylene glycol?

1 Answer
anor277
Jan 24, 2018

So are we talking murder or suicide....or was the man a dipso...?

Explanation:

Ethylene glycol poisoning is not so readily apparent, in that the victim may display symptoms that are consistent with those of intoxication (i.e. over consumption of #H_3C-CH_2OH#).

To get the percentage of ethylene glycol we take the quotient...

#"mass of ethylene glycol"/"mass of solution"xx100%=#

#(103*g)/(340*g)xx100%=30.3%(m"/"m)#...

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