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A compound is 54.53% C, 9.15% H, and 36.32% O by mass. What is its empirical formula?

1 Answer

Feb 26, 2016

#C_2H_4O#

Explanation:

The ratio of no of atoms of C,H&O=#(54.53/12):(9.15/1):(36.32/16)#

=#4.54:9.15:2.27#

=#4.54/2.27:9.15/2.27:2.27/2.27#

=#2:4:1#

Empirical formula #C_2H_4O#

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