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A compound has the empirical formula of #"CH"_2"O"# and a molar mass of 60 g/mole. What is the molecular formula?

1 Answer

Apr 3, 2018

#"C"_2"H"_4"O"_2#

Explanation:

Empirical formula #"= CH"_2"O"#
Empirical formula mass #"= 12g/mol + 2 g/mol + 16 g/mol = 30 g/mol"#

#"Molecular formula mass"/"Empirical formula mass" = "60 g/mol"/"30 g/mol" = 2#

Molecular formula #= 2 × "CH"_2"O" = "C"_2"H"_4"O"_2#

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