A child has three plastic toys bearing the digits 3,3,5 respectively.How many 3-digit numbers can he make using them? Please solve this question without using the formula of permutations of objects not all different which is given by n!/P!×q!.

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Answer 1 · 2017-10-08T00:41:04

Numbers 335, 353, and 533 make a total of 3 numbers possible.

Without going to formulas, we can simply count the number of numbers:

335
353
533

There are 3 numbers possible.