A chemist has a solution that is 20% hydrochloric acid (hcl) and a solution that is 50% hcl. how much of each solution should be mixed to obtain 300 cubic centimeters (cc) of a solution that is 30% hcl?

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Answer 1 · 2017-06-09T13:16:04

Please examine explanation

First acid (20%), amount V (which is volume (in cc))
Second acid (50%), amount $300-V$

Now compute the amounts (volumes)

$0.30times300 = 0.20timesV + 0.50times(300-V)$

$90 = 0.2V + 150 - 0.5V$
$90-150 = -0.3V$
$-60=-0.3V$

$V=200$ cc (from 20% HCl)

The rest (100 cc) should be taken from 50% HCl solution.

Your answer is 200 cc from 20% HCl and 100 cc from 50% HCl solution will do.