A charge of #5 C# is at #(9 , 3 )# and a charge of #-1 C# is at #(-2 , 4 ) #. If both coordinates are in meters, what is the force between the charges?

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A charge of #5 C# is at #(9 , 3 )# and a charge of #-1 C# is at #(-2 , 4 ) #. If both coordinates are in meters, what is the force between the charges?

1 Answer

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Answer 1 · 2016-02-14T18:41:59

#F~=-0,369*10^9N#

Explanation:

#"distance between (9,3) and (-2,4):"#
#r²=(-2-9)^2+(4-3)^2#
#r^2=(-11)^2+1^2#
#r^2=121+1#
#r^2=122#
#"Force between two charges is defined as Coulomb's law"#
#F=(k*q_1*q_2)/r^2#
#F=(k*5*(-1))/122#
#F=(-5*k)/122#
#F=(-5*9*10^9)/122#
#F~=-0,369*10^9N#

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A charge of #5 C# is at #(9 , 3 )# and a charge of #-1 C# is at #(-2 , 4 ) #. If both coordinates are in meters, what is the force between the charges?

1 Answer

Explanation:

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