A charge of #-2 C# is at #(-6, 4 )# and a charge of #-1 C# is at #( -2 , 7) #. If both coordinates are in meters, what is the force between the charges?

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A charge of #-2 C# is at #(-6, 4 )# and a charge of #-1 C# is at #( -2 , 7) #. If both coordinates are in meters, what is the force between the charges?

1 Answer

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Answer 1 · 2016-02-10T19:39:12

#F=72*10^7 N#

Explanation:

#r^2=(-2+6)^2+(7-4)^2#
#r^2=16+9#
#r^2=25" distance between two point"#
#F=(k*q_1*q_2)/(r^2) #
#" Coulomb's law to compute force between two charges"#
#F=(9*10^9*(-2)*(-1))/25#
#F=(2*9*19^9)/25#
#F=0,72*10^9#
#F=72*10^7 N#

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A charge of #-2 C# is at #(-6, 4 )# and a charge of #-1 C# is at #( -2 , 7) #. If both coordinates are in meters, what is the force between the charges?

1 Answer

Explanation:

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