bar (AD)=50* 10/60=50/6=8.33 " miles"¯¯¯¯¯¯AD=50⋅1060=506=8.33 miles
bar(DE)=62*5/60=31/6=5.17" miles"¯¯¯¯¯¯DE=62⋅560=316=5.17 miles
bar(EB)=26*6/60=156/60=2.6 " miles"¯¯¯¯¯¯EB=26⋅660=15660=2.6 miles
bar(AD)=bar(EC)¯¯¯¯¯¯AD=¯¯¯¯¯¯EC
bar(DE)=bar(AC)¯¯¯¯¯¯DE=¯¯¯¯¯¯AC
"use ABC triangle"use ABC triangle
bar(AC)=bar(DE)=5.17¯¯¯¯¯¯AC=¯¯¯¯¯¯DE=5.17
bar(BC)=bar(EC)-bar(EB)¯¯¯¯¯¯BC=¯¯¯¯¯¯EC−¯¯¯¯¯¯EB
bar(BC)=8.33-2.6=5.73¯¯¯¯¯¯BC=8.33−2.6=5.73
"displacement"=bar(AB)=sqrt(bar(AC)^2+bar(BC)^2)displacement=¯¯¯¯¯¯AB=√¯¯¯¯¯¯AC2+¯¯¯¯¯¯BC2
bar(AB)=sqrt((5.17)^2+(5.73)^2)¯¯¯¯¯¯AB=√(5.17)2+(5.73)2
bar(AB)=7.72" miles"¯¯¯¯¯¯AB=7.72 miles
"average velocity is described as " v_a=("displacement")/("time elapsed")average velocity is described as va=displacementtime elapsed
"time elapsed="10/60+5/60+6/60=21/60=0.35 " "htime elapsed=1060+560+660=2160=0.35 h
v_a=(bar(AB))/(0.35)va=¯¯¯¯¯¯AB0.35
v_a=(7.72)/(0.35)va=7.720.35
v_a=22.06 " "mphva=22.06 mph