A car accelerates from 31.0m/s to rest over a displacement of 130.0m. What is the car's acceleration, and how long did it take to stop?

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Answer 1 · 2017-10-11T17:18:02

$a=-3.70ms^(-2)(2dp)$

$t=8.39s(2dp)$

we have

$u=31ms^(-1)$

$v=0ms^(-1)$

$s=130m$

to find $a" & " t$

$color(blue)(v^2=u^2+2as)$

$0=31^2+2xxaxx130$

$0=961+260a$

$:.a=-961/260=-3.70ms^(-2)(2dp)$

$color(blue)(v=u+at)$

$0=31-3.70t$

$t=31/3.70$

$t=8.39s(2dp)$