A candy store merchant sells 25 kg of ju-jubes for $3.00/kg. If he uses one brand selling for $2.25/kg and a second brand selling at $3.75/kg, how much of each brand is required?

1 Answer
May 5, 2017

12.512.5 kg of each brand is required.

Explanation:

Method 1)
Average of selling prices of brand 1 ($2.25)1($2.25) and brand 2 ($3.75)2($3.75) is (3.75+2.25)/2 = $3.03.75+2.252=$3.0 which is also original one $3$3.
So 25/12=12.52512=12.5 kg of each brand is required.

Method 2)

Let quantity of brand 1 required is xx kg and quantity of brand 2 required is yy kg.

So x+y =25 or x=25-yx+y=25orx=25y (1) and x*2.25+y*3.75 = (25*3) or 2.25x + 3.75 y =75x2.25+y3.75=(253)or2.25x+3.75y=75 (2) or 2.25(25-y) +3.75 y =752.25(25y)+3.75y=75
or 56.25 - 2.25y +3.75y =7556.252.25y+3.75y=75 or
1.5y=75-56.25 =18.75 or y= 18.75/1.5 = 12.51.5y=7556.25=18.75ory=18.751.5=12.5 kg :. x=25-y=25-12.5=12.5 kg.

So 12.5 kg of each brand is required. [Ans]