A bullet of mass 2 Kg is having a charge of 2mc. Through what potential difference must it be accelerated, starting from rest, to aquire a speed of 10m/s?

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Answer 1 · 2018-03-16T00:13:10

$50 kV$ $"50 kV"$

Energy due to electric field is

$"U" = "q" Δ"V"$

Energy acquired by bullet is kinetic energy. It’s given by

$"K" = 1/2\ "mv"^2$

$"U = K"$

$"q"Delta"V" = 1/2\ "mv"^2$

$Δ"V" = "mv"^2/"2q" = "2 kg × (10 m/s)"^2/(2 × 2 × 10^-3\ "C") = 5 × 10^4\ "Volt" = "50 kV"$