A buffer solution is formed when 10.0 $cm^3$ of 0.230 mol $dm^-3$ aqueous sodium hydroxide are added to 30.0 $cm^3$ of 0.550 mol $dm^-3$ aqueous propanoic acid. How do you calculate the number of moles of propanoic acid originally present?

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Answer 1 · 2018-05-07T22:06:25

I will assume you don't need this solved, but want a starting point since that is what you're asking.

To calculate the moles of propanoic acid, we do a simple stoichiometric calculation,

$0.030"mL" * (0.550"mol")/"L" approx 1.65*10^-2"mol"$

The same goes for the initial hydroxide added.

A buffer solution is formed when 10.0 cm^3cm^3 of 0.230 mol dm^-3dm^-3 aqueous sodium hydroxide are added to 30.0 cm^3cm^3 of 0.550 mol dm^-3dm^-3 aqueous propanoic acid. How do you calculate the number of moles of propanoic acid originally present?