A body starts from rest and is uniformly accelerated for 30 sec.The distance covered in first 10 sec is $x_1$ , for next 10 sec is $x_2$ and for last 10 sec is $x_3$ the then the ratio of $X_1:X_2:X_3$ =?

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Answer 1 · 2017-04-11T20:34:18

$k=0,1,2,3,....$
$1:3:5:7:(2k+1)$

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$k=0,1,1,3,4...$
$1:3:5:7:(2k+1)$

Answer 2 · 2017-04-12T03:36:22

$x_1:x_2:x_3=1:3:5$

The applicable kinematic expression is
$s=ut+1/2at^2$
$s$ is distance traveled in time $t$ , $u$ is initial velocity and $a$ is acceleration.

Distance traveled in first $10s$
$x_1=0xx10+1/2axx10^2$
$=>x_1=50a$

Distance traveled in next $10 s$
$x_2=s_20-s_10=(0xx20+1/2axx20^2)-50a$
$=>x_2=200a-50a=150a$

Distance traveled in last $10 s$
$x_3=s_30-s_20=(0xx30+1/2axx30^2)-200a$
$=>x_3=450a-200a=250a$

the required ratio is
$x_1:x_2:x_3=50a:150a:250a$
$=>x_1:x_2:x_3=1:3:5$

A body starts from rest and is uniformly accelerated for 30 sec.The distance covered in first 10 sec is x_1x_1 , for next 10 sec is x_2x_2 and for last 10 sec is x_3x_3 the then the ratio of X_1:X_2:X_3X_1:X_2:X_3=?