A block of metal wheighing 2 kg is resting on a frictionless surface,if struck by a jet releasing water at the rate of 1kg/s and at a speed of 5m/s.what is the initial acceleration of the block ?

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A block of metal wheighing 2 kg is resting on a frictionless surface,if struck by a jet releasing water at the rate of 1kg/s and at a speed of 5m/s.what is the initial acceleration of the block ?

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Answer 1 · 2017-01-24T04:15:04

The final velocity of mass of water after hitting the metal block is zero.

So the average change in momentum per sec = initial momentum
$= mass \times initial velocity of water$ $="mass"xx"initial velocity of water"$

$= 1 k g \times 5 m /s = 5 k g m /s$ $=1kgxx5m"/s"=5kgm"/s"$

As this change in momentum occurs during 1 sec. We may say that the force exerted on the 2kg metal block is
$F = \frac{change in momentum}{time}$ $F="change in momentum"/"time"$
$= \frac{5 k g m /s}{1 s} = 5 N$ $=(5kgm"/s")/(1s)=5N$

Hence by Newton's law initial acceleration of the block of mass $m = 2 k g$ $m=2kg$ is given by

$a = \frac{F}{m} = \frac{5 N}{2 k g} = 2.5 m / s^{2}$ $a=F/m=(5N)/(2kg)=2.5m"/"s^2$

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A block of metal wheighing 2 kg is resting on a frictionless surface,if struck by a jet releasing water at the rate of 1kg/s and at a speed of 5m/s.what is the initial acceleration of the block ?

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