A ball is shot out of a cannon. The height of the ball, h in meters, as a function of the time, t in seconds, since it was shot is given by the equation $h= -5t^2 +30t +1$ . What is the height of the ball after 1 second?

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Answer 1 · 2016-03-03T12:16:49

$h="26 m"$

Since this is a function of $t$ , time, the height when $t=1$ can be found by plugging in $1$ for $t$ .

$h=-5(1)^2+30(1)+1$

$h=-5+30+1$

$h="26 m"$

A ball is shot out of a cannon. The height of the ball, h in meters, as a function of the time, t in seconds, since it was shot is given by the equation h= -5t^2 +30t +1h= -5t^2 +30t +1. What is the height of the ball after 1 second?