A balanced lever has two weights on it, the first with mass $9 k g$ $9 kg$ and the second with mass $37 k g$ $37 kg$ . If the first weight is $9 m$ $9 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-12-16T14:03:32

The distance is $= 2.19 m$ $=2.19m$

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The mass $M_{2} = 9 k g$ $M_2=9kg$

The mass $M_{1} = 37 k g$ $M_1=37kg$

The distance $b = 9 m$ $b=9m$

Taking moments about the fulcrum

$M_{1} \times a = M_{2} \times b$ $M_1xxa=M_2xxb$

$a = \frac{M_{2} \times b}{M_{1}} = \frac{9 \times 9}{37} = 2.19 m$ $a=(M_2xxb)/(M_1)=(9xx9)/37=2.19m$

A balanced lever has two weights on it, the first with mass 9 kg 9kg9 kg and the second with mass 37 kg37kg37 kg. If the first weight is 9 m9m 9 m from the fulcrum, how far is the second weight from the fulcrum?