A balanced lever has two weights on it, the first with mass $9 k g$ $9 kg$ and the second with mass $7 k g$ $7 kg$ . If the first weight is $12 m$ $12 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2018-05-08T06:29:01

The distance is $= 15.43 m$ $=15.43m$

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The mass $M_{1} = 9 k g$ $M_1=9kg$

The mass $M_{2} = 7 k g$ $M_2=7kg$

The distance $a = 12 m$ $a=12m$

Taking moments about the fulcrum

$M_{1} \times a = M_{2} \times b$ $M_1xxa=M_2xxb$

$b = \frac{M_{1} \times a}{M_{2}} = \frac{9 \times 12}{7} = 15.43 m$ $b=(M_1xxa)/(M_2)=(9xx12)/(7)=15.43m$

A balanced lever has two weights on it, the first with mass 9kg9 kg and the second with mass 7kg7 kg. If the first weight is 12m 12 m from the fulcrum, how far is the second weight from the fulcrum?