A balanced lever has two weights on it, the first with mass $7 k g$ $7 kg$ and the second with mass $4 k g$ $4 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?

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A balanced lever has two weights on it, the first with mass $7 k g$ $7 kg$ and the second with mass $4 k g$ $4 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-02-03T21:45:51

Weight 2 is $5.25 m$ $5.25m$ from the fulcrum

Explanation:

Moment = Force * Distance

A) Weight 1 has a moment of $21$ $21$ ( $7 k g \times 3 m$ $7kg xx3m$ )

Weight 2 must also have a moment of $21$ $21$

B) $\frac{21}{4} = 5.25 m$ $21/4 = 5.25m$

Strictly speaking the kg should be converted to Newtons in both A and B because Moments are measured in Newton Metres but the gravitational constants will cancel out in B so they were left out for simplicity's sake

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A balanced lever has two weights on it, the first with mass $7 k g$ $7 kg$ and the second with mass $4 k g$ $4 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Explanation:

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Explanation:

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A balanced lever has two weights on it, the first with mass $7 k g$ $7 kg$ and the second with mass $4 k g$ $4 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?