A balanced lever has two weights on it, the first with mass $6 k g$ $6 kg$ and the second with mass $7 k g$ $7 kg$ . If the first weight is $5 m$ $5 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-02-25T15:51:04

The distance is $= 4.28 m$ $=4.28m$

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The load $L = 6 g N$ $L=6gN$

The distance of the load from the fulcrum is $= 5 m$ $=5m$

The effort is $E = 7 g N$ $E=7gN$

The distance of the effort to the fulcrum is $x m$ $xm$

In a situation of equilibrium, the moments are equal

So,

$6 \cdot 5 = 7 \cdot x$ $6*5=7*x$

$x = \frac{30}{7} = 4.28 m$ $x=30/7=4.28m$

A balanced lever has two weights on it, the first with mass 6kg6 kg and the second with mass 7kg7 kg. If the first weight is 5m 5 m from the fulcrum, how far is the second weight from the fulcrum?