A balanced lever has two weights on it, the first with mass $4 k g$ $4 kg$ and the second with mass $1 k g$ $1 kg$ . If the first weight is $8 m$ $8 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-06-03T13:54:43

The distance is $= 32 m$ $=32m$

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The first weight is $M_{1} = 4 g N$ $M_1=4gN$

The second weight is $M_{2} = 1 g N$ $M_2=1gN$

The distance $a = 8 m$ $a=8m$

Taking moments about the fulcrum

$4 g \cdot 8 = 1 g \cdot b$ $4g*8=1g*b$

$b = 32 \frac{g}{g} = 32 m$ $b=32g/g=32m$

The distance is $= 32 m$ $=32m$

A balanced lever has two weights on it, the first with mass 4 kg 4kg4 kg and the second with mass 1 kg1kg1 kg. If the first weight is 8 m8m 8 m from the fulcrum, how far is the second weight from the fulcrum?