A balanced lever has two weights on it, the first with mass $3 k g$ $3 kg$ and the second with mass $4 k g$ $4 kg$ . If the first weight is $8 m$ $8 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2018-03-15T08:07:16

The distance is $= 6 m$ $=6m$

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The first mass is $M_{1} = 3 k g$ $M_1=3kg$

The distance $a = 8 m$ $a=8m$

The second mass is $M_{2} = 4 k g$ $M_2=4kg$

Taking moments about the fulcrum

$M_{2} \times b = M_{1} \times a$ $M_2xxb=M_1xxa$

The distance

$b = \frac{M_{1} \times a}{M_{2}} = \frac{3 \cdot 8}{4} = 6 m$ $b=(M_1xxa)/(M_2)=(3*8)/4=6m$

A balanced lever has two weights on it, the first with mass 3 kg 3kg3 kg and the second with mass 4 kg4kg4 kg. If the first weight is 8 m8m 8 m from the fulcrum, how far is the second weight from the fulcrum?