A balanced lever has two weights on it, the first with mass $3 k g$ $3 kg$ and the second with mass $4 k g$ $4 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-01-31T11:09:52

2.25m

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for Blance, we know,

$\frac{M_{2}}{M_{1}} = \frac{A}{B}$ $M_2/M_1=A/B$

suppose, **B= $x m$ $xm$ **

so,

$\frac{4 k g}{3 k g} = \frac{3}{x}$ $(4kg)/(3kg)=3/x$

$or, x = \frac{3 \times 3}{4}$ $or,x=(3xx3)/4$

$or, x = 2.25$ $or,x=2.25$

A balanced lever has two weights on it, the first with mass 3 kg 3kg3 kg and the second with mass 4 kg4kg4 kg. If the first weight is 3 m3m 3 m from the fulcrum, how far is the second weight from the fulcrum?