A balanced lever has two weights on it, the first with mass $27 k g$ $27 kg$ and the second with mass $18 k g$ $18 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-03-29T05:46:06

The distance is $= 4.5 m$ $=4.5m$

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$M_{2} = 18 g N$ $M_2=18g N$

$a = 3 m$ $a=3m$

$M_{1} = 27 g N$ $M_1=27gN$

Taking moments about the fulcrum

$M_{1} \cdot a = M_{2} \cdot b$ $M_1*a=M_2*b$

$27 g \cdot 3 = 18 g \cdot b$ $27g*3=18g*b$

$b = \frac{27 g \cdot 3}{18 g}$ $b=(27g*3)/(18g)$

$= 4.5 m$ $=4.5m$

A balanced lever has two weights on it, the first with mass 27 kg 27kg27 kg and the second with mass 18 kg18kg18 kg. If the first weight is 3 m3m 3 m from the fulcrum, how far is the second weight from the fulcrum?