A balanced lever has two weights on it, the first with mass $22 k g$ $22 kg$ and the second with mass $24 k g$ $24 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

Question

2084 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-12T09:02:41

The distance is $= 3.67 m$ $=3.67m$

enter image source here

The masses are

$M_{1} = 24 k g$ $M_1=24kg$

$M_{2} = 22 k g$ $M_2=22kg$

The distance $b = 4 m$ $b=4m$

Taking moments about the fulcrum

$M_{1} g \cdot a = M_{2} g \cdot b$ $M_1g*a=M_2g*b$

$a = \frac{M_{2}}{M_{1}} \cdot b = \frac{22}{24} \cdot 4 = 3.67 m$ $a=M_2/M_1*b=22/24*4=3.67m$

The distance is $= 3.67 m$ $=3.67m$

A balanced lever has two weights on it, the first with mass 22kg22 kg and the second with mass 24kg24 kg. If the first weight is 4m 4 m from the fulcrum, how far is the second weight from the fulcrum?