A balanced lever has two weights on it, one with mass $4 k g$ $4 kg$ and one with mass $2 k g$ $2 kg$ . If the first weight is $9 m$ $9 m$ from the fulcrum, how far is the second weight from the fulcrum?

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A balanced lever has two weights on it, one with mass $4 k g$ $4 kg$ and one with mass $2 k g$ $2 kg$ . If the first weight is $9 m$ $9 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-04-01T03:37:29

$18 m$ $18 "m"$

Explanation:

To balance the lever, the torque about the fulcrum must be zero.

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In this question, we have

$M_{1} = 4 kg$ $M_1 = 4 "kg"$
$a = 9 m$ $a = 9 "m"$
$M_{2} = 2 kg$ $M_2 = 2 "kg"$

We want to find $b$ $b$ .

Therefore,

$(4 kg) \cdot (9 m) = (2 kg) \cdot b$ $(4 "kg") * (9 "m") = (2 "kg") * b$

$b = \frac{(4 kg) \cdot (9 m)}{2 kg}$ $b = frac{(4 "kg") * (9 "m")}{2 "kg"}$

$= 18 m$ $= 18 "m"$

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A balanced lever has two weights on it, one with mass $4 k g$ $4 kg$ and one with mass $2 k g$ $2 kg$ . If the first weight is $9 m$ $9 m$ from the fulcrum, how far is the second weight from the fulcrum?

1 Answer

Explanation:

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A balanced lever has two weights on it, one with mass 4 kg4kg4 kg and one with mass 2 kg2kg2 kg. If the first weight is 9 m9m 9 m from the fulcrum, how far is the second weight from the fulcrum?

1 Answer

Explanation:

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A balanced lever has two weights on it, one with mass $4 k g$ $4 kg$ and one with mass $2 k g$ $2 kg$ . If the first weight is $9 m$ $9 m$ from the fulcrum, how far is the second weight from the fulcrum?