A balanced lever has two weights on it, one with mass $2 k g$ $2 kg$ and one with mass $8 k g$ $8 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-12-15T06:42:48

The distance is $= 1 m$ $=1m$

In a state of equilibrium, the moments about the fulcrum of the weights are equal.

Let $d =$ $d=$ distance of second weight from the fulcrum

Moment of first weight $= 2 g \cdot 4 N m$ $=2g*4 Nm$

Moment of second weight $= 8 g \cdot d N m$ $=8g*d Nm$

So,

$2 g \cdot 4 = 8 g \cdot d$ $2g*4=8g*d$

$d = 1 m$ $d=1m$

A balanced lever has two weights on it, one with mass 2kg2 kg and one with mass 8kg8 kg. If the first weight is 4m 4 m from the fulcrum, how far is the second weight from the fulcrum?