A balanced lever has two weights on it, one with mass $12 kg$ and one with mass $15 kg$ . If the first weight is $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2018-04-10T09:29:58

The distance is $=3.2m$

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The mass $M_1=12kg$

The mass $M_2=15kg$

The distance $a=4m$

Taking moments about the fulcrum

$M_1xxa=M_2xxb$

$b=(M_1xxa)/(M_2)=(12*4)/(15)=3.2m$

A balanced lever has two weights on it, one with mass 12 kg12 kg and one with mass 15 kg15 kg. If the first weight is 4 m 4 m from the fulcrum, how far is the second weight from the fulcrum?