A bag contains 9 red marbles and 3 green marbles. How can you find the probability of drawing first one green marble and then one red marble if you do not replace the first marble?

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Answer 1 · 2015-11-02T09:11:22

P(First Marble Green and Second Marble Red) $=9/44$

Probability for the first marble to be green $=3/(9 +3)=3/12=1/4$

Probability for the second marble to be red (marble taken first is not replaced) $=9/(9+(3-1))=9/(9+2)=9/11$

P(First Marble Green and Second Marble Red) $=1/4 xx 9/11=9/44$