A 7.0 µF and a 3.0 µF capacitor are connected in series and this combination is connected in parallel with a 3.9 µF capacitor. What is the net capacitance? in µF

Question

24289 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2014-05-16T13:40:37

To add this combination of capacitors, you first have to add the two series capacitors together using the equation

#1/(C_(series)) = 1/(C_1) + 1/(C_2) + ...#

so you have:

#1/(C_(series)) = 1/(7 µF) + 1/(3 µF) = 3/(21 µF) + 7/(21 µF) = 10/(21 µF) #

so #C_(series) = (21 µF)/10 = 2.1 µF#

Then you add this series combination to the parallel capacitor using the equation:

#C_(par) = C_1 + C_2 + ...#

so

#C_(eq) = 2.1 µF + 3.9 µF = 6 µF#