A 41 kg rock accidentally breaks loose from the edge of a cliff and falls straight down. The magnitude of the air resistance that opposes its downward motion is 260 N. What is the magnitude of the acceleration of the rock?

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Answer 1 · 2015-10-09T15:06:30

$3, 46 m / s^{2}$ $3,46m//s^2$

From Newton's 2nd Law of motion,

$\sum F = m a$ $sumF=ma$

$therefore mg - f_r=ma$

$therefore a=(mg-f_r)/m=((41xx9,8)-260)/41=3,46m//s^2$