A 400 mL sample of oxygen is cooled from 0°C to -40°C. What is the new volume of oxygen? (Assume that the pressure and number of moles has not changed.)

1 Answer
Doc048
Feb 19, 2018

V_(-40^oC) = 341 ml

Explanation:

This is a Charles Law problem where Volume is directly proportional to Temperature. The empirical relationship is

Temp prop Vol => T = kV => k=T/V

For two different Temperature and Volume conditions with Mass and Pressure constant, the relationship is ...

k_1 = k_2 => T_1/V_1 = T_2/V_2

Given:
V_1= 400ml at T_1 = 0^oC=273K (use Kelvin in Empirical Gas Laws)
V_2 = ? at T_2=-40^oC=233K

"273K"/"400ml" = "233K"/V_2 => V_2 = 400ml(233cancel(K))/(273cancel(K)) = 341ml

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