A 3kg stone is dropped from a height of 4m. What is its momentum as it strikes the ground? Solve using suvat

1 Answer
Junaid Mirza
Apr 17, 2018

#"26.55 kgm/s"#

Explanation:

Velocity #("v")# when it hits the ground is

#"v"^2 = "u"^2 + "2aS"#

#"v" = sqrt("u"^2 + "2aS")#

#"v" = sqrt(("0 m/s")^2 + ("2 × 9.8 m/s"^2 × "4 m")) = "8.85 m/s"#

Momentum when it strikes the ground is

#|vec"p"| = "m"|vec"v"| = "3 kg × 8.85 m/s" = color(blue)("26.55 kgm/s")#

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