A 300g ball at rest is struck with a bat with a force of 150N. If the bat was in contact with the ball, for 0.02 seconds, what is the ball's velocity?

1 Answer
Hriman
Feb 26, 2018

vf=10 m/s

Explanation:

We will use the impulse formula
Ftrianglet=mtrianglev
(Ftrianglet)/m=vf-vi
Since vi is zero, solve for vf
(150N*.02 s)/(0.30 kg)=vf
vf=10 m/s

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