A 2.50 kg wood block is pressed against a vertical wood wall by a force applied 34.9° to the horizontal. If the block is initially at rest, and μs=0.493, what force would you need to apply to begin moving the box up the wall?

Question

6338 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-25T08:38:58

#"F"_min=-25.0901 " N"#

negative sign denotes force in opposite direction
pulling instead of pushing at the same angle

#"m"=2.5kg#
#theta=34.9°#
#mu_s=0.493#

enter image source here
[P in image is the applied force]

#"N"="F"costheta#

#"ma"=f_s+"m"g+"F"sintheta=0#
[to start motion, no motion yet: #"a"=0#]

#mu_s"N"+"m"g+"F"sintheta#

#mu_s"N"+"F"sintheta=-"m"g#

#mu_s"F"costheta+"F"sintheta=-"m"g#

#"F"(mu_scostheta+sintheta)=-"m"g#

#"F"=-("m"g)/(mu_scostheta+sintheta)#

Substitute the values

#"F"=-((2.5)(9.8))/(0.493cos34.9°+sin34.9°)#

#"F"_min=-25.0901 " N"#