A 0.75kg block is tied at one end of a rope, 1.5m in length. The block is swung around a vertical circle and rotates four times each minute. (A)what is the centripetal acceleration of the block?

1 Answer
Gió
Jul 4, 2015

I found: a_c=v^2/r=0.26m/s^2

Explanation:

The centripetal acceleration is given as:
a_c=v^2/r
The block completes 4 rotations each minute so it describes 4*2pi radians each 60 seconds giving and angulra velocity of:
omega=(4*2*pi)/60=0.42(rad)/s;
The corresponding linear velocity is:
v=omegar=0.42*1.5=0.63m/s.
So finally:
a_c=v^2/r=(0.63)^2/1.5=0.26m/s^2

Related questions
Impact of this question
1038 views around the world
You can reuse this answer
Creative Commons License