A 0.016 kg silver bracelet has a volume of 9.27 cm^3cm3. What is its density?

1 Answer
anor277
Feb 11, 2017

rho~=1.7*g*cm^-3ρ≅1.7⋅g⋅cm−3

Explanation:

"Density"Density == "Mass"/"Volume"MassVolume == (0.016*kgxx10^3*g*kg^-1)/(9.27*cm^3)0.016⋅kg×103⋅g⋅kg−19.27⋅cm3

=1.73*g*cm^-3=1.73⋅g⋅cm−3

Now chemists would usually use density values of g*mL^-1g⋅mL−1 or g*cm^-3g⋅cm−3. These can be converted into kg*m^-3kg⋅m−3, but these large values are inutile.

Note that I just looked over this question, and the calculated density is ABSURDLY low. So I would review your source. A typical value for silver metal would be rho=10.5*g*cm^-3ρ=10.5⋅g⋅cm−3.

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