74. The equation for the combustion of #CH_4# (the main component of natural gas) is shown below. How much heat is produced by the complete combustion of 237 g of #CH_4#?
#CH_4 (g) + 2O_2 (g) -> CO_2 (g) + 2H_2O (g)#
#DeltaH = -"802.3 kJ/mol"#
1 Answer
Explanation:
The problem provides you with the thermochemical equation that describes the combustion of methane,
#"CH"_ (4(g)) + 2"O"_ (2(g)) -> "CO"_ (2(g)) + 2"H"_ 2"O"_ ((g))" "DeltaH = - "802.3 kJ mol"^(-1)#
The enthalpy change of combustion, given here as
In your case, the enthalpy change of combustion
#DeltaH = -"802.3 kJ mol"^(-1)#
suggests that the combustion of one mole of methane gives off, hence the minus sign,
Your strategy here will be to use the molar mass of methane to convert your sample from grams to moles
#237 color(red)(cancel(color(black)("g"))) * "1 mole CH"_4/(16.04color(red)(cancel(color(black)("g")))) = "14.776 moles CH"_4#
Since you know that
#14.776 color(red)(cancel(color(black)("moles CH"_4))) * overbrace("802.3 kJ"/(1color(red)(cancel(color(black)("mole CH"_4)))))^(color(blue)(= DeltaH)) = "11854.8 kJ"#
Rounded to three sig figs, the answer will be
#"heat produced" = color(green)(|bar(ul(color(white)(a/a)color(black)("11900 kJ")color(white)(a/a)|)))#
This is equivalent to saying that the enthalpy change of reaction,
#DeltaH_"rxn" = -"11900 kJ"#
Keep in mind that the minus sign is used to symbolize heat given off.