Two standard dice are rolled, what is the probability of rolling a pair (both the same number)?

2 Answers
Jun 30, 2018

The probability of rolling the pair

P(E)=1/6~~0.17P(E)=160.17

Explanation:

We note that, if a die is rolled the sample space:

S={1,2,3,4,5,6}S={1,2,3,4,5,6}

We know that ,if two dice rolled the sample space :

S={1,2,3,4,5,6}xx{1,2,3,4,5,6}S={1,2,3,4,5,6}×{1,2,3,4,5,6}

:.S={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),
color(white)(...............)(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),
color(white)(...............)(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),
color(white)(...............)(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),
color(white)(...............)(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),
color(white)(...............)(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

i.e. When two dice are tossed together ,

the possible pairs are : color(blue)(n=6xx6=36

Let ,event E=the same number on both dice.

=> E={(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}

=>no. of comeout pair color(blue)( r=6

So , the probability of rolling the pair =P(E)=r/n

=>P(E)=6/36

=>P(E)=1/6~~0.17

Jun 30, 2018

1/6

Explanation:

Since we are rolling two six-sided dice, there are 6xx6, or 36 different possibilities. This will be our denominator.

How many ways can we get double numbers?

{1,1}, {2,2}, {3,3}, {4,4}, {5,5}, {6,6}

We have 6 different ways of getting double numbers. This is our numerator.

Thus, the probability of rolling pairs is 6/36 or

1/6

Hope this helps!