Question #74a4c
1 Answer
Explanation:
Your starting point here will be to determine how many grams of zinc are present in
You know that zinc sulfide has a molar mass of
Elemental zinc,
Now, the chemical formula of zinc sulfide tells you that
This means that
#5.00 color(red)(cancel(color(black)("g ZnS"))) * "65.38 g Zn"/(97.474 color(red)(cancel(color(black)("g ZnS")))) = "3.354 g Zn"#
So, you know that your crude sample contains
#(3.354 color(red)(cancel(color(black)("g"))))/(8.00color(red)(cancel(color(black)("g")))) * 100% = color(darkgreen)(ul(color(black)(41.9%)))#
The answer is rounded to three sig figs.
Notice that the percent composition of zinc in zinc sulfide
#(3.354 color(red)(cancel(color(black)("g"))))/(5.00color(red)(cancel(color(black)("g")))) * 100% = 67.1%#
if higher than the percent composition of zinc in the crude sample because you're dealing with the same mass of zinc in a smaller mass, i.e. in