Question #68e61

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Answer 1 · 2018-02-02T11:46:56

#146.575K#, or #-126.4^@C#

#VpropT#, where #V# is the volume of the gas and #T# its temperature.

This can become:

#V/T=k#, where #k# is a constant.

It therefore follows that #V_1T_2=V_2T_1#.

We first must convert the temperature to Kelvin: #20^@C+273.15=293.15K#

Input:

#2T_2=1*293.15#

#T_2=293.15/2#

#T_2=146.575K#, or #-126.4^@C#