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Question #97e4c

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Alim K. · Stefan V.

Jan 26, 2018

$MgO$ $"MgO"$ is the empirical formula.

Explanation:

$mol of Mg = \frac{4.9 g}{24 g/mol} = 0.2 mol$ $"mol of Mg" = "4.9 g" /"24 g/mol" = "0.2 mol"$

$mol of O = \frac{3.2 g}{16 g/mol} = 0.2 mol$ $"mol of O" = "3.2 g"/"16 g/mol" = "0.2 mol"$

So the mole ratio is

$0.2 : 0.2 = 1 : 1$ $0.2: 0.2 = 1:1$

Therefore, ${Mg}_{1} O_{1} = MgO$ $"Mg"_1"O"_1 = "MgO"$ is the empirical formula.

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