Question #9ac69

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Question #9ac69

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Answer 1 · 2018-01-02T17:16:04

Please see below.

Explanation:

$42 = 2 \cdot 3 \cdot 7$ $42 = 2*3*7$ and $48 = 2 \cdot 2 \cdot 2 \cdot 2 \cdot 3$ $48 = 2*2*2*2*3$

$G C F = 2 \cdot 3 = 6$ $GCF = 2*3=6$

Note that $42 = 6 \times 7$ $42 = 6 xx 7$ and $48 = 6 \times 8$ $48 = 6 xx 8$ , so

$42 + 48 = 6 \times 7 + 6 \times 8 = 6 \times (7 + 8) = 6 \times 15$ $42+48 = 6 xx 7+6 xx 8 = 6xx(7+8) = 6 xx15$

As long as we're here let's finish.

Method 1: (using the distributuve property)
$6 \times (15) = 6 \times (10 + 5) = 6 \times 10 + 6 \times 5 = 60 + 30 = 90$ $6 xx (15) = 6xx(10+5) = 6xx10+6xx5=60+30 = 90$

Method 2: (using factoring and the associative property of multiplication)
$6 \times 15 = (3 \times 2) \times 15 = 3 \times (2 \times 15) = 3 \times 30 = 90$ $6xx15 = (3xx2)xx15 = 3xx(2xx15) = 3xx30 = 90$

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Question #9ac69

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