Question #875ac

1 Answer

Using various properties of a mol, the volume of one "Hg"Hg atom is "2.44895 * 10^-232.448951023 "cm"^3cm3.

Explanation:

First, let's determine the overall volume of one mole of "Hg"Hg. The molar mass of "Hg"Hg is "200.6 g/mol"200.6 g/mol, so there are "200.6 g"200.6 g of "Hg"Hg in one mole of "Hg"Hg.

We know the number of atoms in one mole, so we'll use "200.6 g"200.6 g as mass. The formula for density is :

d=m/Vd=mV

Switching between the variables will leave us with this:

V=m/dV=md

Substitute the values:

"200.6 g"/"13.6 g/cm"^3 = V200.6 g13.6 g/cm3=V

And you get the volume of one mole as "14.75 cm"^314.75 cm3. The number of atoms in one mol is 6.022 * 10^236.0221023 atoms. Divide the volume by the number of atoms to get 2.44895 * 10^-232.448951023 "cm"^3cm3.