Question #72067

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Question #72067

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Answer 1 · 2017-11-06T07:00:14

The mass is $= 12.9 k g$ $=12.9kg$

Explanation:

Apply the equation of motion

$v = u + a t$ $v=u+at$

to calculate the acceleration

The initial speed is $u = 0 m s^{- 1}$ $u=0ms^-1$

The final speed is $v = 107 m s^{- 1}$ $v=107ms^-1$

The time is $t = 2.3 s$ $t=2.3s$

The acceleration is

$a = \frac{v - u}{t} = \frac{107 - 0}{2.3} = 46.52 m s^{- 2}$ $a=(v-u)/t=(107-0)/2.3=46.52ms^-2$

According to Newton's second Law

$F = m a$ $F=ma$

The force is $F = 600 N$ $F=600N$

The mass is

$m = \frac{F}{a} = \frac{600}{46.52} = 12.9 k g$ $m=F/a=600/46.52=12.9kg$

Answer 2 · 2017-11-06T08:26:38

12.897 kg, or 28.433 lb.

Explanation:

The formula for force, in Newtons $N$ $N$ , is $F = m a$ $F=ma$ , where $F$ $F$ is the force, $m$ $m$ is the mass in $k g$ $kg$ , and $a$ $a$ is the acceleration in $m s^{- 2}$ $ms^-2$ .

The formula for acceleration is $(Deltav)/(Deltat)$ . Here, $Deltav = 107ms^-1$ and $Deltat=2.3s$ .

So the acceleration is $46.522 ms^-2$ .

The formula for force can be rearranged thus:

$F =ma$

$F/a=(mcancelcolor(red)(a))/cancelcolor(red)a$

$m=F/a$

$m=600/46.522$

$m=12.897$

The required mass is 12.897 kg.

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Question #72067

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