Is "iodide anion"iodide anion, I^(-)I, isoelectronic with "xenon"xenon?

1 Answer
Oct 25, 2017

You are correct it would be isoelectronic with the Noble Gas, XeXe...

Explanation:

And thus elemental iodine, the atom, is a reasonably strong oxidant, and we use the "old aufbau principle"old aufbau principle, and distribute 54 electrons.....

I:I: 1s^(2)2s^(2)2p^6 3s^ 2 3p^ 6 3d^ 10 4s^ 2 4p^ 6 4d^ 10 5s^ 2 5p^ 5.1s22s22p63s23p63d104s24p64d105s25p5.

I^(-):I: 1s^(2)2s^(2)2p^6 3s^ 2 3p^ 6 3d^ 10 4s^ 2 4p^ 6 4d^ 10 5s^ 2 5p^ 6.1s22s22p63s23p63d104s24p64d105s25p6. Are there 54 electrons? If not, there should be.

Of course, we must simply remember that when we use iodine, we work with the diatom, I_2I2, as indeed are all of the halogens.....