Is "iodide anion", I^(-), isoelectronic with "xenon"?

1 Answer
Oct 25, 2017

You are correct it would be isoelectronic with the Noble Gas, Xe...

Explanation:

And thus elemental iodine, the atom, is a reasonably strong oxidant, and we use the "old aufbau principle", and distribute 54 electrons.....

I: 1s^(2)2s^(2)2p^6 3s^ 2 3p^ 6 3d^ 10 4s^ 2 4p^ 6 4d^ 10 5s^ 2 5p^ 5.

I^(-): 1s^(2)2s^(2)2p^6 3s^ 2 3p^ 6 3d^ 10 4s^ 2 4p^ 6 4d^ 10 5s^ 2 5p^ 6. Are there 54 electrons? If not, there should be.

Of course, we must simply remember that when we use iodine, we work with the diatom, I_2, as indeed are all of the halogens.....