How many molecules of calcium are in $"463.78 g"$ of calcium?

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Answer 1 · 2017-10-12T18:35:04

Calcium ATOM has a molar mass of $"40.078 g/mol"$ . Therefore:

$463.78 cancel"g Ca" xx "1 mol"/(40.078 cancel"g Ca")$

$=$ $"11.572 mols Ca atom"$

As a result, we have this many atoms:

$11.572 cancel"mols Ca" xx (6.0221413 xx 10^(23) "any atom ever")/(cancel"1 mol any atom ever")$

$= ulcolor(blue)(6.9688 xx 10^24 "atoms Ca")$

How many molecules of calcium are in "463.78 g""463.78 g" of calcium?