Question #99fa3

1 Answer
SCooke
Oct 1, 2017

#15.7g#

Explanation:

With the reaction balanced, the mass balance (conservation of mass) means that the reactants must also total 56.4g. So first, let’s convert the molar ratio into a mass ratio.
#C_4H_(10)O = 74g# #6O_2 = 192g#

The total normalized mass is 266g. We have only 56.4g, so we only have #56.4/266 = 0.212# of a “unit”.
Applying that to the molar ratios, we obtain
#0.212 xx ( C_4H_(10)O + 6O_2) = 0.212# moles #C_4H_(10)O# and #1.27# moles of #O_2#.

#74g/(mol) C_4H_(10)O xx 0.212 = 15.7g#
#32g/(mol) O_2 xx 1.27 = 40.7g#
CHECK: #15.7 + 40.7 = 56.4# CORRECT!

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