Question #99fa3

1 Answer
Oct 1, 2017

15.7g

Explanation:

With the reaction balanced, the mass balance (conservation of mass) means that the reactants must also total 56.4g. So first, let’s convert the molar ratio into a mass ratio.
C_4H_(10)O = 74g 6O_2 = 192g

The total normalized mass is 266g. We have only 56.4g, so we only have 56.4/266 = 0.212 of a “unit”.
Applying that to the molar ratios, we obtain
0.212 xx ( C_4H_(10)O + 6O_2) = 0.212 moles C_4H_(10)O and 1.27 moles of O_2.

74g/(mol) C_4H_(10)O xx 0.212 = 15.7g
32g/(mol) O_2 xx 1.27 = 40.7g
CHECK: 15.7 + 40.7 = 56.4 CORRECT!