Question #36f65

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Question #36f65

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Answer 1 · 2017-09-18T23:58:32

The larger your denominator, the smaller your overall answer.

Explanation:

All fractions are division problems. Doing the math

$\frac{3}{7} \approx 0.429$ $3/7~~0.429$

$\frac{3}{9} \approx 0.333$ $3/9~~0.333$

Thus $\frac{3}{7} ths$ $3/7"ths"$ is greater since the overall unit (represented by the numerator) is divided into fewer pieces. The more pieces you divide a whole into, the smaller each individual piece becomes.

Answer 2 · 2017-09-19T00:28:17

$\frac{3}{7}$ $3/7$ is greater than $\frac{3}{9}$ $3/9$ .

Explanation:

$\frac{3}{7}$ $3/7$ and $\frac{3}{9}$ $3/9$ have common denominator $7 \cdot 9 = 63$ $7*9 = 63$

$\frac{3}{7} = \frac{3 \cdot 9}{7 \cdot 9} = \frac{27}{63}$ $3/7 = (3*9)/(7*9) = 27/63$

$\frac{3}{9} = \frac{3 \cdot 7}{9 \cdot 7} = \frac{21}{63}$ $3/9 = (3*7)/(9*7) = 21/63$

Since $27 > 21$ $27 > 21$ , we see that $\frac{27}{63} > \frac{21}{63}$ $27/63 > 21/63$ .

So $\frac{3}{7} > \frac{3}{9}$ $3/7 > 3/9$

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Question #36f65

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