How many gold atoms are there in a $5.37*mol$ quantity of the metal?

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Answer 1 · 2017-09-13T15:13:41

How many? Well, $5.37*molxxN_A.....$

How many? Well, $5.37*molxxN_A.....$ where $N_A="Avogadro's number"$ , $6.022xx10^23*mol^-1$ .

And so we takes the product....

$5.37*molxx6.022xx10^23*mol^-1=3.23xx10^24$ individual gold atoms; pretty vast but not infinite.

The current price of gold is $$1,323.86*USD*oz^-1$ . Given that $1*oz-=28.3*g$ , how much is this molar quantity of gold worth?

How many gold atoms are there in a 5.37*mol5.37*mol quantity of the metal?