A cube of titanium metal contains 3.10xx10^23*"titanium atoms". What is the edge length of the cube if rho_"titanium"=4.5*g*cm^3?

1 Answer
Sep 11, 2017

Well, we know that N_A titanium atoms have a mass of 47.87*g. Did I know that number from the top of my head? From where did I get it?

Explanation:

And since N_A=6.022xx10^23*mol^-1, we take the quotient.....

"Mass of Ti"=(3.10xx10^23*"Ti atoms")/(6.022xx10^23*"Ti atoms"*mol^-1)xx47.87*g*mol^-1=24.64*g..........

And we know that rho, "density"="Mass"/"Volume"

But the volume of a cube is r^3, where r is the length of the sides of the cube.....

And so rho="Mass"/"Volume", "Volume"=r^3="Mass"/rho

r=""^(3)sqrt("Mass"/"Density")=""^(3)sqrt((24.64*g)/(4.5*g*cm^-3))=1.76*cm